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=Y^2-2Y-49
We move all terms to the left:
-(Y^2-2Y-49)=0
We get rid of parentheses
-Y^2+2Y+49=0
We add all the numbers together, and all the variables
-1Y^2+2Y+49=0
a = -1; b = 2; c = +49;
Δ = b2-4ac
Δ = 22-4·(-1)·49
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10\sqrt{2}}{2*-1}=\frac{-2-10\sqrt{2}}{-2} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10\sqrt{2}}{2*-1}=\frac{-2+10\sqrt{2}}{-2} $
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